Armstrong Number II

C++ PROGRAMS

The following program gives you all the 3 digit numbers which are Armstrong Numbers.

In this I will use for loop and if statement.

Code:

#include<iostream.h>

#include<conio.h>

void main()

{

clrscr();

int a,b,c,i;

cout<<"3-Digit Armstrong Numbers"<<"\n";

for(i=100;i<=999;i++)

{

 a=i%10;

 b=i/10;

 b=b%10;

 c=1/100;

 a=a*a*a;

 b=b*b*b;

 c=c*c*c;

 if(i!=a+b+c)

 continue; 

 cout<<i<<"\n";

}

getch();

} 

Output:

  

For determining whether any 3-digit number entered by the user is an Armstrong number or not please go through Armstrong Number I .

For any queries or suggestions please comment !